Given:
The mass of each ball, m=0.20 kg
The initial velocity of the first ball, u=1.6 m/s
The velocity of the stationary ball after the collision, v₂=1.2 m/s
To find:
The speed of the first ball after the collision.
Explanation:
From the law of conservation of momentum, the total momentum of a system always remains the same.
Thus,
[tex]\begin{gathered} mu=mv_1+mv_2 \\ \Rightarrow u=v_1+v_2 \end{gathered}[/tex]Where v₁ is the velocity of the 1st ball.
On substituting the known values,
[tex]\begin{gathered} 1.6=v_1+1.2 \\ \Rightarrow v_1=1.6-1.2 \\ =0.4\text{ m/s} \end{gathered}[/tex]Final answer:
The speed of the 1st ball aft
