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The wheel on a vehicle has a rotational inertia of 3 kg⋅m2. At the instant the wheel has a counterclockwise angular velocity of 8 rad/s, an average counterclockwise torque of 6 N⋅m is applied, and continues for 2 s. What is the change in angular momentum of the wheel?Question 1 options:2 kg⋅m2/s24 kg⋅m2/s12 kg⋅m2/s16 kg⋅m2/s18 kg⋅m2/s3 kg⋅m2/s

Respuesta :

Answer:

12 kg⋅m²/s

Explanation:

The change in angular momentum can be calculated as

[tex]\Delta L=\tau\Delta t[/tex]

Where τ es the torque and Δt is the time. Replacing τ = 6 N m and Δt = 2s, we get

[tex]\begin{gathered} \Delta L=(6\text{ N}\cdot m)(2\text{ s\rparen} \\ \Delta L=12\text{ kg m}^2\text{ /s} \end{gathered}[/tex]

Therefore, the answer is

12 kg⋅m²/s

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