contestada

A small homemade electromagnet has a lifting force of 3.6 N. If the current through the coil is doubled and the number of loops is tripled, what will the lifting force become?

Respuesta :

We will determmine the lifting force as follows:

[tex]F=\frac{NI\mu}{L}[/tex]

Now, using tthe equation for the magnetic force we will have the following scenario:

[tex]F=\frac{3N\cdot2I\mu}{L}\Rightarrow F=6\cdot\frac{NI\mu}{L}[/tex][tex]\Rightarrow F=3.6\cdot6\Rightarrow F=21.6[/tex]

Thus:

[tex]F\approx22[/tex]

So, the lifting force will be exactñy 21.6N, that is approximately 22N.

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