The sample space for selecting 2 students from the 10 students contains
[tex]10C2=45[/tex]On the other hand, the number of ways of selecting 1 boy and 1 girl is
[tex]6C1\times4C1=6\times4=24[/tex]Then, the probability of selecting 1 boy and 1 girls is
[tex]P(1\text{ boy and 1 girl)=}\frac{6C1\times4C1}{10C2}=\frac{24}{45}[/tex]then, by reducing this fraction the answer is
[tex]P(1\text{ boy and 1 girl)=}\frac{8}{15}[/tex]which corresponds to option C
