We know that the equation area is:
[tex]A\text{ = }\pi r^2[/tex]and we also know that the diameter is
[tex]\begin{gathered} d\text{ = 2r} \\ r\text{ = }\frac{d}{2} \end{gathered}[/tex]So in this case we have that
[tex]\begin{gathered} A\text{ = }\pi\cdot(8m)^2 \\ =\pi\cdot64\operatorname{cm}=201.06cm^2 \\ \cong\text{ 201}cm^2 \end{gathered}[/tex]The answer is: 201cm2
