Draw the image of ABC under the translation (x, y) + (x + 2, Y + 2). y 6+ 5- 3 2 1+ -7 -6 5 4 3 2 2 3 5 6 7 -2 B -3- -5- -6 2 of 4

The translation is (x,y)->(x+2,y+2). To draw the ABC under the translation we have to translate the points A(-2,2), B(-5,-2) and C(-6,4).
The translation correspond to add 2 units to the x-value and 2 units to the y-value. So the triangle ABC transform to A'B'C', the points A', B' and C' are:
[tex]\begin{gathered} A(-2,2)\to A^{\prime}(-2+2,2+2)=A^{\prime}(0,4) \\ B(-5,-2)\to B^{\prime}(-5+2,-2+2)=B^{\prime}(-3,0) \\ C(-6,4)\to C^{\prime}(-6+2,4+2)=C^{\prime}(-4,6) \end{gathered}[/tex]