If v varies with t², then equation is,
[tex]\begin{gathered} v\propto t^2 \\ v=kt^2 \end{gathered}[/tex]
Here, k is constant.
Substitute 6 for v and 8 for t in the equation to determine the value of constant k.
[tex]\begin{gathered} 6=k(8)^2 \\ 6=64k \\ k=\frac{6}{64} \end{gathered}[/tex]
The value of constant k is 6/64. So equation for v is,
[tex]v=\frac{6}{64}t^2[/tex]
