To find the loss values we have to find the equation of the line .
The slope is given by:
[tex]m=\frac{y_2-y_1}{x_2-x_1}[/tex]
We are going to take the points:
(2 , 6) and (5 , 3)
Notice that both points are part of the graph.
Replacing:
[tex]m=\frac{3-6}{5-2}=\frac{-3}{3}=-1[/tex]
The slope is equal to -1.
Now, the equation of the line in the slope-intercep form is given by:
[tex]y=mx+b[/tex]
Replacing the point (2 , 6) and the slope m=-1 to find the y-intersect (b):
[tex]\begin{gathered} 6=-1*2+b \\ b=6+2=8 \end{gathered}[/tex]
The equation of the line is:
[tex]y=-x+8[/tex]
Finally, we are going to find the loss during the first year, it means x=1. Substituing:
[tex]y=-1+8=7[/tex]
Answer: The loss during the first year was 7 thousands of dollars.
