First, we solve for y the second equation to get the following:
[tex]\begin{gathered} 2x-3y=-18 \\ \Rightarrow2x+18=3y \\ \Rightarrow y=\frac{2x+18}{3} \end{gathered}[/tex]now we substitute this expression on the irst equation to find the value of the x-coordinate of the solution:
[tex]\begin{gathered} 4x+5\cdot(\frac{2x+18}{3})=8 \\ \Rightarrow4x+\frac{10x+90}{3}=8 \\ \text{ Multiplying both sides by 3 we get:} \\ (4x+\frac{10x+90}{3}=8)\cdot3 \\ \Rightarrow12x+10x+90=24 \\ \Rightarrow22x=24-90=-66 \\ \Rightarrow x=-\frac{66}{22}=-3 \\ x=-3 \end{gathered}[/tex]therefore, x=-3
