Given:
Given a figure.
The radius of the semicircle is 4 inches.
The side of the square is 8 inches.
Required:
To find the area.
Explanation:
The area of the square isA
[tex]\begin{gathered} A1=a^2 \\ \\ =8^2 \\ \\ =64 \end{gathered}[/tex]
Area of the semicircle is
[tex]\begin{gathered} A2=\frac{1}{2}\pi r^2 \\ \\ =\frac{1}{2}\times3.14\times4^2 \\ \\ =\frac{50.24}{2} \\ \\ =25.12 \end{gathered}[/tex]
Now the total area is
[tex]\begin{gathered} =A1+4(A2) \\ \\ =64+4(25.12) \\ \\ =164.48 \end{gathered}[/tex]
Final Answer:
The area of the figure is 164.48 square inches.
