An observer (0) is located 400 feet from a building (B). The observer notices a kite (K) flying at a 29° angle ofelevation from his line of sight. How high is the kite flying over the building? You must show all work andcalculations.

Explanation
here we have a rigth triangle, so we need to use trigonometric functions
then, let
[tex]\begin{gathered} \text{hyupotenuse}=OK \\ \text{adjacent side = 400} \\ \text{angle = 29 \degree} \\ \text{opposite side=KB} \end{gathered}[/tex]therefore, we need a function that relates those variables
[tex]\tan \Theta=\frac{opposite\text{ side}}{\text{adjacent side}}[/tex]replace
[tex]\begin{gathered} \tan \Theta=\frac{opposite\text{ side}}{\text{adjacent side}} \\ \tan \text{ 29=}\frac{KB}{400} \\ solve\text{ for KB} \\ KB=400\cdot\tan \text{ 29} \\ KB=221.723 \\ \text{rounded} \\ KB=222\text{ m} \end{gathered}[/tex]I hope this helps you
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