Answer:
x = 30 degrees
x = 60 degrees
Explanation:
Given the below trig function;
[tex]\sin 2x=\frac{\sqrt[]{3}}{2}[/tex]
To solve for x, let's take the inverse sine of both sides of the equation, we'll have;
[tex]\begin{gathered} 2x=\sin ^{-1}(\sqrt[]{\frac{3}{2})} \\ 2x=60 \\ x=\frac{60}{2} \\ x=30^{\circ} \end{gathered}[/tex]
To find the 2nd solution, we know that, in the 1st and 2nd quadrants, the sine function is always positive. So we'll have;
[tex]\begin{gathered} 2x=(180-60) \\ 2x=120 \\ x=\frac{120}{2} \\ x=60^{\circ} \end{gathered}[/tex]
