Help with #18 please. find the missing side. Round to the nearest tenth

Let's use the law of sines:
[tex]\begin{gathered} \frac{x}{\sin(48)}=\frac{16}{\sin (42)} \\ solve_{\text{ }}for_{\text{ }}x\colon \\ x=\frac{16\sin (48)}{\sin (42)} \\ x=17.8 \end{gathered}[/tex]