Let H represent the whole number of hours that the plumber works.
We were told that he's considering a plumber that charges an initial fee of $65 along with an hourly rate of $28. This means that if he hires this plumber for H hours, the expression for the total cost would be
65 + 28H
Anand would like to spend no more than $250. This means that the amount that he wnats to spend is lesser than or equal to $250.
1) If he hires the plumber, the inequality that describes this scenario would be
[tex]65\text{ + 28H }\leq250[/tex]2) We would solve for H. It becomes
[tex]\begin{gathered} 65\text{ + 28H }\leq250 \\ 28H\text{ }\leq250\text{ - 65} \\ 28H\text{ }\leq185 \\ H\text{ }\leq\frac{185}{28} \\ H\leq6.61 \end{gathered}[/tex]Since the number of hours must be whole numbers, then the largest whole number of hours that anand can afford is 6 hours. This is so because the next whole number is 7 hours and that would be more than he can afford