Answer: Provided the side length which is 4in, and the formulas for both perimeter and the area, we have to evaluate each of the two:
[tex]\begin{gathered} A=s^2\rightarrow1 \\ P=s\rightarrow2 \end{gathered}[/tex]
Area is:
[tex]\begin{gathered} \begin{equation*} A=s^2 \end{equation*} \\ \therefore\rightarrow \\ A=(4in)^2 \\ A=4in\times4i\text{ }=16in^2 \\ A=16in^2 \end{gathered}[/tex]
Perimeter is:
[tex]\begin{gathered} P=4s \\ P=4\times4=16 \\ P=16in \end{gathered}[/tex]
