Given :
Total number of balls = 50
Required: odds against it being G39
This implies we are to solve for the
[tex]\frac{probability\text{ }o\text{f not picking a ball labelled G39}}{probability\text{ of picking a ball labelled G39}}[/tex]
Probability of not picking a ball labelled G39
[tex]\begin{gathered} P(not\text{ G39) = 1 - P(G39)} \\ =\text{ 1 - }\frac{1}{50} \\ =\frac{49}{50} \end{gathered}[/tex]
Probability of picking a ball labelled G39
[tex]P(G39)\text{ = }\frac{1}{50}[/tex]
Odds against picking a ball labelled G39
[tex]\begin{gathered} =\frac{49}{50}\text{ : }\frac{1}{50} \\ =\text{ 0.98 : 0.02} \\ =49\text{ : 1} \end{gathered}[/tex]
