As per given by the question,
There are given that the equation
[tex]4(2-3t)+6t=-6t+8[/tex]Now,
First expand the given equation
So,
[tex]\begin{gathered} 4(2-3t)+6t=-6t+8 \\ 8-12t+6t=-6t+8 \end{gathered}[/tex]Then,
[tex]\begin{gathered} 8-12t+6t=-6t+8 \\ 8-6t=-6t+8 \\ 8-6t+6t-8=0 \\ 8-0-8=0 \\ 8-8=0 \\ 0=0 \end{gathered}[/tex]Hence, the value are true for all t.
