Explanation
Step 1
isolate y
[tex]\begin{gathered} y+4=-3(x-6) \\ \text{break the parenthesis} \\ y+4=-3x+18 \\ \text{subtrac 4 in both sides} \\ y+4-4=-3x+18-4 \\ y=-3x+14 \end{gathered}[/tex]
Step 2
now, we need 2 points or coordinates from the line, to do that we need
input a value for x to obtain the y value, so
a) when x= 4
replace in the equation and calculate}
[tex]\begin{gathered} y=-3x+14 \\ y=-3(4)+14 \\ y=-12+14 \\ y=2 \\ so,\text{ the coordinate is ( 4,2)} \end{gathered}[/tex]
P1(4,2)
b)when x= 6
[tex]\begin{gathered} y=-3x+14 \\ y=-3(6)+14 \\ y=-18+14 \\ y=-4 \\ so,\text{ the coordinate is ( 6,-4)} \end{gathered}[/tex]
P2(6,-4)
Step 3
finally, draw a line that passes through point P1 and P2
I hope this helps you
