Given:
[tex](0,375)\text{ and (}5,325)\text{ are the points lie on the line.}[/tex][tex]\begin{gathered} \text{Slope(m)}=\frac{y_2-y_1}{x_2-x_1} \\ \text{Slope(m)}=\frac{325-375}{5-0} \\ \text{Slope(m)}=-\frac{50}{5} \\ \text{Slope(m)}=-10 \end{gathered}[/tex][tex]y-\text{intercept(b)}=375[/tex]
Equation of the line is
[tex]\begin{gathered} y=mx+b \\ y=-10x+375 \end{gathered}[/tex]
If (0,375) is not given , Finding method of y-intercept.
We have an general equation y= -10x+b.
Point (10,275) is passing through the line
[tex]\begin{gathered} 275=-10(10)+b \\ 275=-100+b \\ 275+100=b \\ b=375 \end{gathered}[/tex]
