Given data:
* The time taken by object is,
[tex]\begin{gathered} t=11.3\text{ min} \\ t=\text{ 678 s} \end{gathered}[/tex]* The velocity given is,
[tex]v=1.2ms^{-1}[/tex]Solution:
The displacement in the given case is,
[tex]\begin{gathered} d=vt \\ d=1.2\times678 \\ d=813.6\text{ m} \end{gathered}[/tex]Thus, the displacement in the given case is 813.6 m.
