Respuesta :

Remember the laws of exponents:

[tex]\frac{a^n}{a^m}=a^{n-m}[/tex]

Then:

[tex]\begin{gathered} \frac{3^{100}}{3^{99}}=3^{100-99} \\ =3^1 \\ =3 \end{gathered}[/tex]

Therefore:

[tex]\frac{3^{100}}{3^{99}}=3[/tex]

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