Given
We have
[tex](\frac{8}{27})^{\frac{1}{3}}[/tex]Required
we need to find its value
Explanation
here we know that when basis are same powers are added
[tex](\frac{8}{27})^{\frac{1}{3}}=(\frac{2\times2\times2}{3\times3\times3})^{\frac{1}{3}}=(\frac{2^3}{3^3})^{\frac{1}{3}}=\frac{2^{3\times\frac{1}{3}}}{3^{3\times\frac{1}{3}}}=\frac{2}{3}[/tex]so the required answer is
[tex]\frac{2}{3}[/tex]