Given function:
[tex]f(x)=x^2-8x+11[/tex]
Finding x when f(x) = -4
[tex]x^2-8x+11=-4[/tex][tex]\begin{gathered} x^2-8x+15=0 \\ x^2-5x-3x+15=0 \end{gathered}[/tex][tex]\begin{gathered} x(x-5)-3(x-5)=0 \\ (x-3)(x-5)=0 \\ x=3,5 \end{gathered}[/tex]
Thus, the value of x is 3 and 5.
