To solve this problem we have to use the rule of dilutions:
[tex]V1\cdot C1=V2\cdot C2[/tex]Where V1 is the initial volume, C1 is the initial concentration, V2 is the final volume and C2 is the final concentration.
Replace V1 for 0.560L, C1 for 43.6% and C2 for 20.4% and solve the equation for V2:
[tex]\begin{gathered} V2=\frac{V1\cdot C1}{C2} \\ V2=\frac{0.560L\cdot43.6\%}{20.4\%} \\ V2=1.20L \end{gathered}[/tex]It means that the final volume is 1.20L.
