Consider the given poynomial,
[tex]P(x)=3x-8[/tex]
(a)
Substitute x=0 in the polynomial,
[tex]\begin{gathered} P(0)=3(0)-8 \\ P(0)=0-8 \\ P(0)=-8 \end{gathered}[/tex]
Thus, 3x-8 is equal to -8 when 'x' equals 0.
(b)
Substitute x=-1 in the polynomial,
[tex]\begin{gathered} P(-1)=3(-1)-8 \\ P(-1)=-3-8 \\ P(-1)=-11 \end{gathered}[/tex]
Thus, 3x-8 is equal to -11 when 'x' equals -1.
