Respuesta :
Given:
There are given that the length of a rectangle is 1 inch more than the width.
Explanation:
Suppose the value of width is x.
Then,
According to the question, the length of a rectangle is 1 inch more than the width:
So,
The value of width is;
[tex]x+1[/tex]Now,
From the formula of area of a rectangle:
[tex]\begin{gathered} A=length\times width \\ 20=(x+1)\times x \\ 20=x^2+x \\ x^2+x-20=0 \end{gathered}[/tex]Then,
[tex]\begin{gathered} x^{2}+x-20=0 \\ (x-4)(x+5)=0 \\ x=4,-5 \end{gathered}[/tex]Then,
Put the value of x, i.e., 4, into the length and width.
So,
[tex]\begin{gathered} width=x=4 \\ length=x+1=4+1=5 \end{gathered}[/tex]Final answer:
Hence, the dimension of the rectangle is shown below:
[tex]\begin{gathered} length=5 \\ width=4 \end{gathered}[/tex]