To check which one is not the solution of
[tex]2x+3y=12[/tex]
we can substitute x and y with their values.
Let's test in order.
(0, 4) is:
[tex]\begin{gathered} x=0 \\ y=4 \\ 2\cdot0+3\cdot4=0+12=12 \end{gathered}[/tex]
It matches the result, so it is a solution.
(3, 2) is:
[tex]\begin{gathered} x=3 \\ y=2 \\ 2\cdot3+3\cdot2=6+6=12 \end{gathered}[/tex]
It matches the result, so it is a solution.
(2, 3) is:
[tex]\begin{gathered} x=2 \\ y=3 \\ 2\cdot2+3\cdot3=4+9=13 \end{gathered}[/tex]
It doesn't match the result, so it is not a solution.
Thus, the correct answer is (2, 3).
