Respuesta :

Sum of consecutives

A + B + C + D = 28

B= A+2, C= A+2+2 ,D= A+2+2+2

Then

A+(A+2)+(A+4)+A+6= 28

A+A+A+A+2+4+6 = 28

4•A = 28- 2-4-6

then A = (28-12)/4 = 4

then consecutive evens are

4,6,8,10

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