Given:
There are four cards numbered as
[tex]3,\text{ }4,\text{ }5,\text{ and }6.[/tex]
Required:
We have to find the probability of picking a 6 and then picking a 3.
Explanation:
When you pick a card at random there are four possibilities.
The possibility of picking a 6 is only one.
Hence the probability of picking a 6 on the first card is
[tex]\frac{1}{4}[/tex]
Since you have put back the first card so in the second card there are again four possibilities.
The possibility of picking a 3 is only one.
Hence the probability of picking a 3 on the second card is
[tex]\frac{1}{4}[/tex]
Hence the probability of picking a 6 and then picking a 3 is
[tex]\frac{1}{4}\times\frac{1}{4}=\frac{1}{16}[/tex]
Final answer:
Hence the final answer is
[tex]\frac{1}{16}[/tex]
