Determine the surface area of box.
[tex]\begin{gathered} SA=2(\frac{3}{2}\cdot\frac{4}{3}+\frac{3}{2}\cdot2+\frac{4}{3}\cdot2) \\ =2(2+3+\frac{8}{3}) \\ =2(\frac{23}{3}) \\ =\frac{46}{3} \end{gathered}[/tex]So wrapping paper required for one box is 46/3 square feet.
Determine the wraping paper for 3 boxes.
[tex]\frac{46}{3}\cdot3=46[/tex]So 46 square feet of wrapping paper is required for 3 boxes.
Draw a net to represent one box.
