Equation of the line
The equation of a line in slope-intercept form is:
y = mx + b
Where m is the slope and b is the y-intercept.
We are required to find the equation of a line that is perpendicular to the line
y = 5x + 4
and passes through the point (-5,2)
The first thing we need to do is to calculate the slope of the required line.
The slope of the given line is m1=5. Two lines are perpendicular if their slopes satisfy the equation:
m1 * m2 = -1
Solving for m2:
[tex]m_2=-\frac{1}{m_1}=-\frac{1}{5}[/tex]The equation of the required line is:
[tex]y=-\frac{1}{5}x+b[/tex]To find the value of b, we substitute the given point (-5,2):
[tex]2=-\frac{1}{5}(-5)+b[/tex]Operating:
[tex]2=1+b[/tex]Solving for b:
b = 1
Finally, our equation is:
[tex]y=-\frac{1}{5}x+1[/tex]