[tex]\begin{gathered} x^2=8y \\ \\ \text{the x-intercept is found when x=0} \\ 8y=0 \\ y=0 \\ \\ \text{ The x-intercept and the y-intercept is (0,0)} \\ \\ \\ \text{The domain is where y is defined "over " x, that means, the values of x that give a y. } \\ \\ D=\text{All real numbers} \\ \\ \text{The domain is all real numbers } \\ \\ \text{And we see that since } \\ x^2=(-x)^2 \\ \\ \text{ the axis of symmetry is x=0!} \end{gathered}[/tex][tex]\begin{gathered} \text{ For 2, we will graph the Parabola using some points, and representing the equaiton in another way} \\ y=\frac{x^2}{8} \\ \\ \\ x=-2\text{ y=1/2} \\ x=-1\text{ y=1/8} \\ x=0\text{ y=0 } \\ x=1\text{ y=1/8} \\ x=2\text{ y=1/2} \end{gathered}[/tex]
Then we plot the points and join them with a line
