Solution
The slant height l = 10 cm
Using Pythagoras theorem
The height of the cone is
[tex]\begin{gathered} h=\sqrt{l^2-h^2} \\ \\ \Rightarrow\sqrt{10^2-6^2}=\sqrt{100-36}=\sqrt{64}=8 \end{gathered}[/tex]
Hence, the height is 8 cm
The formula for the Lateral surface area is given as;
[tex]\begin{gathered} A_L=\pi rl \\ \\ A_L=\pi\times6\times10=60\pi\text{ cm}^2 \end{gathered}[/tex]
