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A sample of gas in a closed container at a temperature of 66°C and a pressure of 5 atm is heated to 352°C. What pressure does the gas exert at the higher temperature?Answer in units of atm.

Respuesta :

Answer

P2 = 9.218 atm

Explanation

Given:

Initial temperature (T1) = 66 °C = 339 K

Final temperature (T2) = 352 °C = 625 K

Initial pressure (P1) = 5 atm

Required: Final pressure (P2)

Solution

To solve this problem we will use Gay-Lussac's Law

P1/T1 = P2/T2

we want to solve for P2

P2 = P1T2/T1

P2 = (5 atm x 625 K)/339K

P2 = 9.218 atm

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