Given data:
The given equation of ellipe is
[tex]\begin{gathered} \frac{(x+2)^2}{36}+\frac{(y-3)^2}{9}=1 \\ \frac{(x+2)^2}{6^2}+\frac{(y-3)^2}{3^2}=1 \end{gathered}[/tex]
The eccentricity of the ellipse is,
[tex]\begin{gathered} e=\sqrt[]{1-\frac{b^2}{a^2}} \\ =\sqrt[]{1-\frac{9}{36}} \\ =\sqrt[]{\frac{25}{36}} \\ =\frac{5}{6} \end{gathered}[/tex]
The focii is,
[tex]\begin{gathered} (3,6e)\text{ , (3,-6e)} \\ (3,5),\text{ (3,-5)} \end{gathered}[/tex]
Thus, the focii is (3,5), (3,-5) and eccentricity is 5/6 and lips are horizontal as major axis is greater than minor axis.
