In order to find u and v, we apply trigonometric ratios
[tex]\begin{gathered} \sin 60^0=\frac{\text{ opposite}}{\text{hypotenuse}}=\frac{u}{4} \\ \frac{\sqrt[]{3}}{2}=\frac{u}{4} \\ u=2\sqrt[]{3} \end{gathered}[/tex][tex]\begin{gathered} \cos 60^0=\frac{v}{4} \\ v=4\times\frac{1}{2}\text{ = 2} \end{gathered}[/tex]
Therefore, u = 2√3, v = 2.
The right option is A.
