Given:
[tex]a=12,b=9\text{ and c=4}[/tex]
Required:
Find the value of the expression
[tex]\frac{bc^2+a}{c}[/tex]
Explanation:
The given expression is
[tex]\frac{bc^{2}+a}{c}[/tex]
Substitute the values of a,b, and c in the expression.
[tex]\begin{gathered} \frac{bc^{2}+a}{c}=\frac{(9)(4)^2+12}{4} \\ =\frac{9(16)+12}{4} \\ =\frac{144+12}{4} \\ =\frac{156}{4} \\ =39 \end{gathered}[/tex]
Final Answer:
The value of the expression is 39.
