As given by the question
There are given that the expression
[tex]g(x)=\sqrt[3]{4x-48}[/tex]
Now,
Put the value of x=-4 into the given expression
[tex]\begin{gathered} g(x)=\sqrt[3]{4x-48} \\ g(-4)=\sqrt[3]{4(-4)-48} \\ g(-4)=\sqrt[3]{-16-48} \\ g(-4)=\sqrt[3]{-64} \\ g(-4)=((-4)^3)^{\frac{1}{3}} \\ g(-4)=-4 \end{gathered}[/tex]
Hence, the value of g(-4) is -4.
