Respuesta :

We will have the following:

[tex]E_1=h\ast f\Rightarrow E_1=(6.626\ast10^{-34}J\ast Hz)(3.17\ast10^{11}Hz)\Rightarrow E_1\approx2.1\ast10^{-22}J[/tex]

So, the solution will be:

[tex]2.10\ast10^{-22}J[/tex]

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