ANSWER:
[tex]n\leq-4\text{ or }n>2[/tex]
STEP-BY-STEP EXPLANATION:
We have the following compound inequality
[tex]n+1\leq-3\text{ or }-4n<-8[/tex]
solving por n
[tex]\begin{gathered} n+1\leq-3\text{ } \\ n+1-1\leq-3-1 \\ n\leq-4 \\ \\ -4n<8 \\ n>\frac{8}{-4} \\ n>2 \\ \\ \text{ we combine and we have} \\ n\leq-4\text{ or }n>2 \\ (-\infty,-4\rbrack\cup(2,\infty) \end{gathered}[/tex]
The graph is:
