We will have the following:
Since the figure is reflected over the lines y = -2 and y = -10 (Is relfected over the x-axis) we will have that the distance between the figue and it's pre-images will be:
*For the image over y = -2:
[tex]d=2\sqrt[]{(-2-y)^2}\Rightarrow d=2|-y-2|[/tex]*For the image over y = -10:
[tex]d=2\sqrt[]{(-10-y)^2}\Rightarrow d=2|-y-10|[/tex]The reason the y is in the answer for both is that the distance (or at leas the points of the figure) are not known, so y represents the distance between the figure and the reflection axis; and the reason it is multiplied by two is that the distance between the image and the pre-image is twice the distance between the figure and the reflection axis.
