Answer:
Part a) x=-3, x = 0, x = 2
Part b) p(x) → ∞
Explanations:
a) The given function is:
p(x) = x (x + 3)(x - 2)
The zeros of the function are gotten by setting p(x) = 0
0 = x (x + 3) (x - 2)
x = 0
x + 3 = 0, x = -3
x - 2 = 0, x = 2
The zeros of the function p(x) are -3, 0, 2
b) As x → ∞
P(x) → ∞
