The initial slope of the graph is one
Using the equation a straight line
Since this is a straight line graph
y = mx + c
m is the slope
c is the intercept
le y be g(x)
m = f(x)
g(x) = f(x) *x + c
our new slope is 5 and intercept = 2
g(x) = 5x + 2
from the new equation we can find one points
to find x let g(x) = 0
0 = 5x +2
-5x = 2
x = -2/5
to find g(x) let x = 0
g(x) = 5(0) +2
g(x) = 0+2
g(x) = 2
our new points is (-2/5, 2)
the new graph will be a neg
