Solution
For this case we can use the compound interest formula given by:
[tex]A=P(1+\frac{r}{n})^{nt}[/tex]and for this case A= 5000, r = 0.06, t= 4 and n = 1 ( compounded yearly)
[tex]A=5000(1+\frac{0.06}{1})^{1\cdot4}=6312.38[/tex]and the interest would be:
[tex]i=6312.38-5000=1312.38[/tex]