The general equation for a circle is given by:
[tex]\begin{gathered} (x-h)^2+(y-k)^2=r^2 \\ \text{where:} \\ \text{center}=(h,k) \\ r=\text{radius} \\ \end{gathered}[/tex]For this equation:
[tex]x^2+y^2=49[/tex]We can rewrite it as:
[tex]x^2+y^2=7^2[/tex]Therefore:
h = 0
k = 0
r = 7
Hence, the answer is:
a circle with center (0, 0) and radius 7
