From 2001 to 2012 the sales for a local doughnut store increased by about the same percent each year. The sales, S, for yeart can be modeled by S = 372,300(5/6)^t, where t= 0 corresponds to 2001. What were the sales in 2001?

Respuesta :

Given the sales for year t is represented by the expression below:

[tex]S\text{ = 372300(}\frac{5}{6})^t[/tex]

Where t = 0 corresponds to 2001.

To find the sales in 2001, substitute t for 0 in the equation above:

[tex]S=372300(\frac{5}{6})^0\text{ = 372300(1) = 372300}[/tex]

Therefore, the sales in 2001 is 372300

ANSWER:

372,300