Solution:
The equation is given below as
[tex]logx+log4=log12[/tex]By applying the logarithm law of multiplication, we will have
[tex]logM+logN=logMN[/tex]By substituting the values, we will have
[tex]\begin{gathered} logx+log4=log12 \\ log(4\times x)=log12 \\ 4x=12 \\ \frac{4x}{4}=\frac{12}{4} \\ x=3 \end{gathered}[/tex]Hence,
The value of x is
[tex]\Rightarrow x=3[/tex]