94846.5grams
Given the following parameters
molecules of Al2O3 = 5.6 x 10^26 molecules
According to the avogadros constant
1 mole = 6.02 * 10^23 molecules
Convert molecules to moles
[tex]\begin{gathered} moles\text{ of Al}_2O_3=\frac{5.6\times10^{26}}{6.02\times10^{23}} \\ moles\text{ of Al}_2O_3=0.9302\times10^3 \\ moles\text{ of Al}_2O_3=930.2moles \end{gathered}[/tex]Convert the moles to mass
[tex]\begin{gathered} mass\text{ of Al}_2O_3=moles\times molar\text{ mass} \\ mass\text{ of Al}_2O_3=930.2\cancel{moles}\times\frac{101.96g}{\cancel{mole}} \\ mass\text{ of Al}_2O_3=94,846.5grams \end{gathered}[/tex]Therefore the mass of 5.6 x 10^26 molecules of Al2O3 is 94846.5grams
