For the 30° - 60° right triangle, we have:
Then, if BC = 8 = √(3) k:
[tex]\begin{gathered} 8=\sqrt{3}k \\ \\ k=\frac{8}{\sqrt{3}} \\ \\ \Rightarrow k=\frac{8\sqrt{3}}{3} \end{gathered}[/tex]
From the figure:
[tex]\begin{gathered} AB=k \\ \\ \therefore AB=\frac{8\sqrt{3}}{3} \end{gathered}[/tex]
