[tex]\begin{gathered} \text{The equation is,} \\ -3y=4x+10 \\ y=-\frac{4}{3}x-\frac{10}{3} \\ So,\text{ the slope is}\Rightarrow m=-\frac{4}{3} \\ \text{Now for parallel line equation} \\ y-y_1=m(x-x_1) \\ y-7=-\frac{4}{3}(x+18) \\ 3y-21=-4x-72 \\ 3y=-4x-51 \\ y=-\frac{4}{3}x-17 \end{gathered}[/tex]
